10001320033 has 4 divisors (see below), whose sum is σ = 10001734848. Its totient is φ = 10000905220.

The previous prime is 10001320027. The next prime is 10001320057. The reversal of 10001320033 is 33002310001.

10001320033 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 33002310001 = 17 ⋅1941312353.

It is a cyclic number.

It is not a de Polignac number, because 10001320033 - 2⁵ = 10001320001 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10001319995 and 10001320022.

It is not an unprimeable number, because it can be changed into a prime (10001320093) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 168853 + ... + 220258.

It is an arithmetic number, because the mean of its divisors is an integer number (2500433712).

Almost surely, 2^10001320033 is an apocalyptic number.

It is an amenable number.

10001320033 is a deficient number, since it is larger than the sum of its proper divisors (414815).

10001320033 is an equidigital number, since it uses as much as digits as its factorization.

10001320033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 414814.

The product of its (nonzero) digits is 54, while the sum is 13.

Adding to 10001320033 its reverse (33002310001), we get a palindrome (43003630034).

The spelling of 10001320033 in words is "ten billion, one million, three hundred twenty thousand, thirty-three".