1000132300113 has 4 divisors (see below), whose sum is σ = 1333509733488. Its totient is φ = 666754866740.

The previous prime is 1000132300067. The next prime is 1000132300133. The reversal of 1000132300113 is 3110032310001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1000132300113 - 2⁸ = 1000132299857 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1000132300092 and 1000132300101.

It is not an unprimeable number, because it can be changed into a prime (1000132300133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 166688716683 + ... + 166688716688.

It is an arithmetic number, because the mean of its divisors is an integer number (333377433372).

Almost surely, 2^{1000132300113} is an apocalyptic number.

It is an amenable number.

1000132300113 is a deficient number, since it is larger than the sum of its proper divisors (333377433375).

1000132300113 is an equidigital number, since it uses as much as digits as its factorization.

1000132300113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 333377433374.

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 1000132300113 its reverse (3110032310001), we get a palindrome (4110164610114).

The spelling of 1000132300113 in words is "one trillion, one hundred thirty-two million, three hundred thousand, one hundred thirteen".