1000133121131 has 4 divisors (see below), whose sum is σ = 1000436103264. Its totient is φ = 999830139000.

The previous prime is 1000133121079. The next prime is 1000133121133. The reversal of 1000133121131 is 1311213310001.

1000133121131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1000133121131 - 2²² = 1000128926827 is a prime.

It is a super-2 number, since 2×1000133121131² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1000133121133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 151486115 + ... + 151492716.

It is an arithmetic number, because the mean of its divisors is an integer number (250109025816).

Almost surely, 2^{1000133121131} is an apocalyptic number.

1000133121131 is a deficient number, since it is larger than the sum of its proper divisors (302982133).

1000133121131 is an equidigital number, since it uses as much as digits as its factorization.

1000133121131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 302982132.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 1000133121131 its reverse (1311213310001), we get a palindrome (2311346431132).

The spelling of 1000133121131 in words is "one trillion, one hundred thirty-three million, one hundred twenty-one thousand, one hundred thirty-one".