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10001341323 = 33370420049
BaseRepresentation
bin10010101000010000…
…00101101110001011
3221211000021210002000
421110020011232023
5130440320410243
64332231242043
7502561666341
oct112410055613
927730253060
1010001341323
114272550846
121b31519323
13c35069b5c
146ac3d1991
153d80755d3
hex254205b8b

10001341323 has 8 divisors (see below), whose sum is σ = 14816802000. Its totient is φ = 6667560864.

The previous prime is 10001341291. The next prime is 10001341379. The reversal of 10001341323 is 32314310001.

10001341323 is a `hidden beast` number, since 1 + 0 + 0 + 0 + 1 + 341 + 323 = 666.

It is not a de Polignac number, because 10001341323 - 25 = 10001341291 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10001341296 and 10001341305.

It is not an unprimeable number, because it can be changed into a prime (10001341393) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 185209998 + ... + 185210051.

It is an arithmetic number, because the mean of its divisors is an integer number (1852100250).

Almost surely, 210001341323 is an apocalyptic number.

10001341323 is a deficient number, since it is larger than the sum of its proper divisors (4815460677).

10001341323 is an equidigital number, since it uses as much as digits as its factorization.

10001341323 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 370420058 (or 370420052 counting only the distinct ones).

The product of its (nonzero) digits is 216, while the sum is 18.

Adding to 10001341323 its reverse (32314310001), we get a palindrome (42315651324).

The spelling of 10001341323 in words is "ten billion, one million, three hundred forty-one thousand, three hundred twenty-three".

Divisors: 1 3 9 27 370420049 1111260147 3333780441 10001341323