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10002312113 = 27067369539
BaseRepresentation
bin10010101000010111…
…10010101110110001
3221211002010002202012
421110023302232301
5130441042441423
64332304132305
7502603151543
oct112413625661
927732102665
1010002312113
114273054152
121b31907095
13c353199a1
146ac5a5693
153d81b8078
hex2542f2bb1

10002312113 has 4 divisors (see below), whose sum is σ = 10002708720. Its totient is φ = 10001915508.

The previous prime is 10002312091. The next prime is 10002312119. The reversal of 10002312113 is 31121320001.

10002312113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10002312113 - 210 = 10002311089 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (10002312119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 157703 + ... + 211836.

It is an arithmetic number, because the mean of its divisors is an integer number (2500677180).

Almost surely, 210002312113 is an apocalyptic number.

It is an amenable number.

10002312113 is a deficient number, since it is larger than the sum of its proper divisors (396607).

10002312113 is an equidigital number, since it uses as much as digits as its factorization.

10002312113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 396606.

The product of its (nonzero) digits is 36, while the sum is 14.

Adding to 10002312113 its reverse (31121320001), we get a palindrome (41123632114).

The spelling of 10002312113 in words is "ten billion, two million, three hundred twelve thousand, one hundred thirteen".

Divisors: 1 27067 369539 10002312113