1000252153 has 4 divisors (see below), whose sum is σ = 1000581988. Its totient is φ = 999922320.

The previous prime is 1000252151. The next prime is 1000252177. The reversal of 1000252153 is 3512520001.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 745945344 + 254306809 = 27312^2 + 15947^2 .

It is a cyclic number.

It is not a de Polignac number, because 1000252153 - 2¹ = 1000252151 is a prime.

It is a super-2 number, since 2×1000252153² = 2001008739162270818, which contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1000252153.

It is not an unprimeable number, because it can be changed into a prime (1000252151) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 160326 + ... + 166447.

It is an arithmetic number, because the mean of its divisors is an integer number (250145497).

Almost surely, 2^1000252153 is an apocalyptic number.

It is an amenable number.

1000252153 is a deficient number, since it is larger than the sum of its proper divisors (329835).

1000252153 is an equidigital number, since it uses as much as digits as its factorization.

1000252153 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 329834.

The product of its (nonzero) digits is 300, while the sum is 19.

The square root of 1000252153 is about 31626.7632393832. The cubic root of 1000252153 is about 1000.0840439364.

Adding to 1000252153 its reverse (3512520001), we get a palindrome (4512772154).

It can be divided in two parts, 1000252 and 153, that added together give a triangular number (1000405 = T₁₄₁₄).

The spelling of 1000252153 in words is "one billion, two hundred fifty-two thousand, one hundred fifty-three".