10003242014433 has 20 divisors (see below), whose sum is σ = 15822121358340. Its totient is φ = 6276544008192.

The previous prime is 10003242014413. The next prime is 10003242014497. The reversal of 10003242014433 is 33441024230001.

10003242014433 is a `hidden beast` number, since 1 + 0 + 0 + 0 + 3 + 24 + 201 + 4 + 433 = 666.

It can be written as a sum of positive squares in 2 ways, for example, as 4963881512529 + 5039360501904 = 2227977^2 + 2244852^2 .

It is not a de Polignac number, because 10003242014433 - 2⁴² = 5605195503329 is a prime.

It is a super-2 number, since 2×10003242014433² (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a junction number, because it is equal to n+sod(n) for n = 10003242014397 and 10003242014406.

It is not an unprimeable number, because it can be changed into a prime (10003242014413) by changing a digit.

It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 3632257888 + ... + 3632260641.

It is an arithmetic number, because the mean of its divisors is an integer number (791106067917).

Almost surely, 2^{10003242014433} is an apocalyptic number.

It is an amenable number.

10003242014433 is a deficient number, since it is larger than the sum of its proper divisors (5818879343907).

10003242014433 is an equidigital number, since it uses as much as digits as its factorization.

10003242014433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7264518558 (or 7264518549 counting only the distinct ones).

The product of its (nonzero) digits is 6912, while the sum is 27.

Adding to 10003242014433 its reverse (33441024230001), we get a palindrome (43444266244434).

The spelling of 10003242014433 in words is "ten trillion, three billion, two hundred forty-two million, fourteen thousand, four hundred thirty-three".