100033120113 has 4 divisors (see below), whose sum is σ = 133377493488. Its totient is φ = 66688746740.

The previous prime is 100033120087. The next prime is 100033120151. The reversal of 100033120113 is 311021330001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 100033120113 - 2¹³ = 100033111921 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 100033120092 and 100033120101.

It is not an unprimeable number, because it can be changed into a prime (100033120153) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16672186683 + ... + 16672186688.

It is an arithmetic number, because the mean of its divisors is an integer number (33344373372).

Almost surely, 2^100033120113 is an apocalyptic number.

It is an amenable number.

100033120113 is a deficient number, since it is larger than the sum of its proper divisors (33344373375).

100033120113 is an equidigital number, since it uses as much as digits as its factorization.

100033120113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 33344373374.

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 100033120113 its reverse (311021330001), we get a palindrome (411054450114).

The spelling of 100033120113 in words is "one hundred billion, thirty-three million, one hundred twenty thousand, one hundred thirteen".