10003334055713 has 4 divisors (see below), whose sum is σ = 10003354864020. Its totient is φ = 10003313247408.

The previous prime is 10003334055683. The next prime is 10003334055721. The reversal of 10003334055713 is 31755043330001.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 5796499238464 + 4206834817249 = 2407592^2 + 2051057^2 .

It is a cyclic number.

It is not a de Polignac number, because 10003334055713 - 2⁸ = 10003334055457 is a prime.

It is a super-3 number, since 3×10003334055713³ (a number of 40 digits) contains 333 as substring.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (10003334055773) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9665570 + ... + 10650347.

It is an arithmetic number, because the mean of its divisors is an integer number (2500838716005).

Almost surely, 2^{10003334055713} is an apocalyptic number.

It is an amenable number.

10003334055713 is a deficient number, since it is larger than the sum of its proper divisors (20808307).

10003334055713 is an equidigital number, since it uses as much as digits as its factorization.

10003334055713 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 20808306.

The product of its (nonzero) digits is 56700, while the sum is 35.

Adding to 10003334055713 its reverse (31755043330001), we get a palindrome (41758377385714).

The spelling of 10003334055713 in words is "ten trillion, three billion, three hundred thirty-four million, fifty-five thousand, seven hundred thirteen".