Base | Representation |
---|---|
bin | 1001000110010011111011… |
… | …1110001001111100000011 |
3 | 1022102101011102101102011122 |
4 | 2101210332332021330003 |
5 | 2302401231020012121 |
6 | 33135442415502455 |
7 | 2051524215056366 |
oct | 221447676117403 |
9 | 38371142342148 |
10 | 10004035313411 |
11 | 3207762147787 |
12 | 1156a23227a2b |
13 | 5774b8192539 |
14 | 2682ab0360dd |
15 | 1253643415ab |
hex | 9193ef89f03 |
10004035313411 has 4 divisors (see below), whose sum is σ = 10005305352432. Its totient is φ = 10002765274392.
The previous prime is 10004035313359. The next prime is 10004035313417. The reversal of 10004035313411 is 11431353040001.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 10004035313411 - 242 = 5605988802307 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (10004035313417) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 635007695 + ... + 635023448.
It is an arithmetic number, because the mean of its divisors is an integer number (2501326338108).
Almost surely, 210004035313411 is an apocalyptic number.
10004035313411 is a deficient number, since it is larger than the sum of its proper divisors (1270039021).
10004035313411 is an equidigital number, since it uses as much as digits as its factorization.
10004035313411 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1270039020.
The product of its (nonzero) digits is 2160, while the sum is 26.
Adding to 10004035313411 its reverse (11431353040001), we get a palindrome (21435388353412).
The spelling of 10004035313411 in words is "ten trillion, four billion, thirty-five million, three hundred thirteen thousand, four hundred eleven".
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