Base | Representation |
---|---|
bin | 1001000110010011111101… |
… | …0000001100001010011001 |
3 | 1022102101011202021121100201 |
4 | 2101210333100030022121 |
5 | 2302401233222303423 |
6 | 33135443105102201 |
7 | 2051524303206646 |
oct | 221447720141231 |
9 | 38371152247321 |
10 | 10004040041113 |
11 | 3207764886778 |
12 | 1156a24927961 |
13 | 5774b91593b1 |
14 | 2682ab906dcd |
15 | 1253649772ad |
hex | 9193f40c299 |
10004040041113 has 8 divisors (see below), whose sum is σ = 10015018305408. Its totient is φ = 9993062786784.
The previous prime is 10004040041057. The next prime is 10004040041119. The reversal of 10004040041113 is 31114004040001.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 10004040041113 - 225 = 10004006486681 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (10004040041119) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 20502820 + ... + 20985082.
It is an arithmetic number, because the mean of its divisors is an integer number (1251877288176).
Almost surely, 210004040041113 is an apocalyptic number.
It is an amenable number.
10004040041113 is a deficient number, since it is larger than the sum of its proper divisors (10978264295).
10004040041113 is an equidigital number, since it uses as much as digits as its factorization.
10004040041113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 504983.
The product of its (nonzero) digits is 192, while the sum is 19.
Adding to 10004040041113 its reverse (31114004040001), we get a palindrome (41118044081114).
The spelling of 10004040041113 in words is "ten trillion, four billion, forty million, forty-one thousand, one hundred thirteen".
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