Base | Representation |
---|---|
bin | 11101000111011001011… |
… | …11001101011011010011 |
3 | 10112122012220000111022001 |
4 | 32203230233031123103 |
5 | 112342311434231121 |
6 | 2043325050054431 |
7 | 132163643330653 |
oct | 16435457153323 |
9 | 3478186014261 |
10 | 1000404211411 |
11 | 3562a6107a10 |
12 | 141a7541a417 |
13 | 73450c52ca7 |
14 | 365c3dc6363 |
15 | 1b051eac991 |
hex | e8ecbcd6d3 |
1000404211411 has 4 divisors (see below), whose sum is σ = 1091350048824. Its totient is φ = 909458374000.
The previous prime is 1000404211369. The next prime is 1000404211459. The reversal of 1000404211411 is 1141124040001.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 1000404211411 - 29 = 1000404210899 is a prime.
It is a super-2 number, since 2×10004042114112 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1000404211711) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 45472918690 + ... + 45472918711.
It is an arithmetic number, because the mean of its divisors is an integer number (272837512206).
Almost surely, 21000404211411 is an apocalyptic number.
1000404211411 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
1000404211411 is a deficient number, since it is larger than the sum of its proper divisors (90945837413).
1000404211411 is an equidigital number, since it uses as much as digits as its factorization.
1000404211411 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 90945837412.
The product of its (nonzero) digits is 128, while the sum is 19.
Adding to 1000404211411 its reverse (1141124040001), we get a palindrome (2141528251412).
The spelling of 1000404211411 in words is "one trillion, four hundred four million, two hundred eleven thousand, four hundred eleven".
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