100040423113009 has 4 divisors (see below), whose sum is σ = 100070456266480. Its totient is φ = 100010389959540.

The previous prime is 100040423112977. The next prime is 100040423113039. The reversal of 100040423113009 is 900311324040001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 100040423113009 - 2⁵ = 100040423112977 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (100040423113039) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15016571739 + ... + 15016578400.

It is an arithmetic number, because the mean of its divisors is an integer number (25017614066620).

Almost surely, 2^{100040423113009} is an apocalyptic number.

It is an amenable number.

100040423113009 is a deficient number, since it is larger than the sum of its proper divisors (30033153471).

100040423113009 is an equidigital number, since it uses as much as digits as its factorization.

100040423113009 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 30033153470.

The product of its (nonzero) digits is 2592, while the sum is 28.

The spelling of 100040423113009 in words is "one hundred trillion, forty billion, four hundred twenty-three million, one hundred thirteen thousand, nine".