10004421331 has 4 divisors (see below), whose sum is σ = 10015452472. Its totient is φ = 9993390192.

The previous prime is 10004421313. The next prime is 10004421359. The reversal of 10004421331 is 13312440001.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 10004421331 - 2⁵ = 10004421299 is a prime.

It is a super-2 number, since 2×10004421331² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10004421299 and 10004421308.

It is not an unprimeable number, because it can be changed into a prime (10004421391) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5514210 + ... + 5516023.

It is an arithmetic number, because the mean of its divisors is an integer number (2503863118).

Almost surely, 2^10004421331 is an apocalyptic number.

10004421331 is a deficient number, since it is larger than the sum of its proper divisors (11031141).

10004421331 is an equidigital number, since it uses as much as digits as its factorization.

10004421331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11031140.

The product of its (nonzero) digits is 288, while the sum is 19.

Adding to 10004421331 its reverse (13312440001), we get a palindrome (23316861332).

The spelling of 10004421331 in words is "ten billion, four million, four hundred twenty-one thousand, three hundred thirty-one".