Base | Representation |
---|---|
bin | 1001000110010111111100… |
… | …1110011110100011111011 |
3 | 1022102110221112212112102112 |
4 | 2101211333032132203323 |
5 | 2302410433003142021 |
6 | 33140141405322535 |
7 | 2051563015100525 |
oct | 221457716364373 |
9 | 38373845775375 |
10 | 10005113334011 |
11 | 320816570a5a4 |
12 | 115708426644b |
13 | 57762a618b53 |
14 | 268370292a15 |
15 | 1253c8cd4d5b |
hex | 9197f39e8fb |
10005113334011 has 4 divisors (see below), whose sum is σ = 10017450096024. Its totient is φ = 9992776572000.
The previous prime is 10005113333923. The next prime is 10005113334043. The reversal of 10005113334011 is 11043331150001.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 10005113334011 - 214 = 10005113317627 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (10005113334071) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6168379790 + ... + 6168381411.
It is an arithmetic number, because the mean of its divisors is an integer number (2504362524006).
Almost surely, 210005113334011 is an apocalyptic number.
10005113334011 is a deficient number, since it is larger than the sum of its proper divisors (12336762013).
10005113334011 is an equidigital number, since it uses as much as digits as its factorization.
10005113334011 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 12336762012.
The product of its (nonzero) digits is 540, while the sum is 23.
Adding to 10005113334011 its reverse (11043331150001), we get a palindrome (21048444484012).
The spelling of 10005113334011 in words is "ten trillion, five billion, one hundred thirteen million, three hundred thirty-four thousand, eleven".
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