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100054714139 = 385125981489
BaseRepresentation
bin101110100101110111…
…0011100011100011011
3100120020222121002221022
41131023232130130123
53114403001323024
6113544155433055
710141310015642
oct1351356343433
9316228532838
10100054714139
11394843066a6
121748415578b
139586c58783
144bb2424359
152908e4635e
hex174bb9c71b

100054714139 has 4 divisors (see below), whose sum is σ = 100080699480. Its totient is φ = 100028728800.

The previous prime is 100054714127. The next prime is 100054714141. The reversal of 100054714139 is 931417450001.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 100054714139 - 28 = 100054713883 is a prime.

It is a super-2 number, since 2×1000547141392 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 100054714099 and 100054714108.

It is not an unprimeable number, because it can be changed into a prime (100054714189) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12986894 + ... + 12994595.

It is an arithmetic number, because the mean of its divisors is an integer number (25020174870).

Almost surely, 2100054714139 is an apocalyptic number.

100054714139 is a deficient number, since it is larger than the sum of its proper divisors (25985341).

100054714139 is an equidigital number, since it uses as much as digits as its factorization.

100054714139 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 25985340.

The product of its (nonzero) digits is 15120, while the sum is 35.

The spelling of 100054714139 in words is "one hundred billion, fifty-four million, seven hundred fourteen thousand, one hundred thirty-nine".

Divisors: 1 3851 25981489 100054714139