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10005553114435 = 531179479359663
BaseRepresentation
bin1001000110011001100101…
…1100000110110101000011
31022102112002012101200202101
42101212121130012311003
52302412333044130220
633140253155331231
72051606635134304
oct221463134066503
938375065350671
1010005553114435
11320837098609a
1211571875b0b17
1357769a778058
142683b28507ab
1512540270530a
hex91999706d43

10005553114435 has 16 divisors (see below), whose sum is σ = 12394078986240. Its totient is φ = 7746169972320.

The previous prime is 10005553114397. The next prime is 10005553114441. The reversal of 10005553114435 is 53441135550001.

It is not a de Polignac number, because 10005553114435 - 29 = 10005553113923 is a prime.

It is a super-2 number, since 2×100055531144352 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 10005553114394 and 10005553114403.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 27639414 + ... + 27999076.

It is an arithmetic number, because the mean of its divisors is an integer number (774629936640).

Almost surely, 210005553114435 is an apocalyptic number.

10005553114435 is a deficient number, since it is larger than the sum of its proper divisors (2388525871805).

10005553114435 is a wasteful number, since it uses less digits than its factorization.

10005553114435 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 539178.

The product of its (nonzero) digits is 90000, while the sum is 37.

Adding to 10005553114435 its reverse (53441135550001), we get a palindrome (63446688664436).

The spelling of 10005553114435 in words is "ten trillion, five billion, five hundred fifty-three million, one hundred fourteen thousand, four hundred thirty-five".

Divisors: 1 5 31 155 179479 359663 897395 1798315 5563849 11149553 27819245 55747765 64551955577 322759777885 2001110622887 10005553114435