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100101133113 = 335299455099
BaseRepresentation
bin101110100111001111…
…1100001001100111001
3100120101012221102210120
41131032133201030321
53120001342224423
6113552534403453
710142412410142
oct1351637411471
9316335842716
10100101133113
11394a8530993
1217497800589
13959375bc17
144bb8668ac9
15290d064ee3
hex174e7e1339

100101133113 has 8 divisors (see below), whose sum is σ = 133506012000. Its totient is φ = 66715171488.

The previous prime is 100101133051. The next prime is 100101133123. The reversal of 100101133113 is 311331101001.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 100101133113 - 29 = 100101132601 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 100101133092 and 100101133101.

It is not an unprimeable number, because it can be changed into a prime (100101133123) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4716963 + ... + 4738136.

It is an arithmetic number, because the mean of its divisors is an integer number (16688251500).

Almost surely, 2100101133113 is an apocalyptic number.

It is an amenable number.

100101133113 is a deficient number, since it is larger than the sum of its proper divisors (33404878887).

100101133113 is an equidigital number, since it uses as much as digits as its factorization.

100101133113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9458631.

The product of its (nonzero) digits is 27, while the sum is 15.

Adding to 100101133113 its reverse (311331101001), we get a palindrome (411432234114).

The spelling of 100101133113 in words is "one hundred billion, one hundred one million, one hundred thirty-three thousand, one hundred thirteen".

Divisors: 1 3 3529 10587 9455099 28365297 33367044371 100101133113