Base | Representation |
---|---|
bin | 11101001000100001111… |
… | …01110010010001010011 |
3 | 10112200210020200222010020 |
4 | 32210100331302101103 |
5 | 112400033033341430 |
6 | 2043505241234523 |
7 | 132215003466453 |
oct | 16442075622123 |
9 | 3480706628106 |
10 | 1001012012115 |
11 | 356588203645 |
12 | 142004a92a43 |
13 | 73519b5038b |
14 | 366409ddd63 |
15 | 1b08a51bb10 |
hex | e910f72453 |
1001012012115 has 8 divisors (see below), whose sum is σ = 1601619219408. Its totient is φ = 533873073120.
The previous prime is 1001012012101. The next prime is 1001012012123. The reversal of 1001012012115 is 5112102101001.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 1001012012115 - 211 = 1001012010067 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (15), and also a Moran number because the ratio is a prime number: 66734134141 = 1001012012115 / (1 + 0 + 0 + 1 + 0 + 1 + 2 + 0 + 1 + 2 + 1 + 1 + 5).
It is a junction number, because it is equal to n+sod(n) for n = 1001012012094 and 1001012012103.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 33367067056 + ... + 33367067085.
It is an arithmetic number, because the mean of its divisors is an integer number (200202402426).
Almost surely, 21001012012115 is an apocalyptic number.
1001012012115 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1001012012115 is a deficient number, since it is larger than the sum of its proper divisors (600607207293).
1001012012115 is an equidigital number, since it uses as much as digits as its factorization.
1001012012115 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 66734134149.
The product of its (nonzero) digits is 20, while the sum is 15.
Adding to 1001012012115 its reverse (5112102101001), we get a palindrome (6113114113116).
The spelling of 1001012012115 in words is "one trillion, one billion, twelve million, twelve thousand, one hundred fifteen".
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