100101504001201 has 4 divisors (see below), whose sum is σ = 100101683161600. Its totient is φ = 100101324840804.

The previous prime is 100101504001193. The next prime is 100101504001217. The reversal of 100101504001201 is 102100405101001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 100101504001201 - 2³ = 100101504001193 is a prime.

It is a super-3 number, since 3×100101504001201³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (100101504001801) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 88739481 + ... + 89860438.

It is an arithmetic number, because the mean of its divisors is an integer number (25025420790400).

Almost surely, 2^{100101504001201} is an apocalyptic number.

It is an amenable number.

100101504001201 is a deficient number, since it is larger than the sum of its proper divisors (179160399).

100101504001201 is an equidigital number, since it uses as much as digits as its factorization.

100101504001201 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 179160398.

The product of its (nonzero) digits is 40, while the sum is 16.

Adding to 100101504001201 its reverse (102100405101001), we get a palindrome (202201909102202).

The spelling of 100101504001201 in words is "one hundred trillion, one hundred one billion, five hundred four million, one thousand, two hundred one".