10010303123131 has 4 divisors (see below), whose sum is σ = 10010320677000. Its totient is φ = 10010285569264.

The previous prime is 10010303123083. The next prime is 10010303123203. The reversal of 10010303123131 is 13132130301001.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 10010303123131 - 2¹⁵ = 10010303090363 is a prime.

It is a super-2 number, since 2×10010303123131² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10010303123099 and 10010303123108.

It is not an unprimeable number, because it can be changed into a prime (10010303123231) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7891786 + ... + 9071983.

It is an arithmetic number, because the mean of its divisors is an integer number (2502580169250).

Almost surely, 2^{10010303123131} is an apocalyptic number.

10010303123131 is a deficient number, since it is larger than the sum of its proper divisors (17553869).

10010303123131 is an equidigital number, since it uses as much as digits as its factorization.

10010303123131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 17553868.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 10010303123131 its reverse (13132130301001), we get a palindrome (23142433424132).

The spelling of 10010303123131 in words is "ten trillion, ten billion, three hundred three million, one hundred twenty-three thousand, one hundred thirty-one".