10010333113 has 4 divisors (see below), whose sum is σ = 10920363408. Its totient is φ = 9100302820.

The previous prime is 10010333051. The next prime is 10010333143. The reversal of 10010333113 is 31133301001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31133301001 = 11 ⋅2830300091.

It is a cyclic number.

It is not a de Polignac number, because 10010333113 - 2²⁵ = 9976778681 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (10010333143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 455015131 + ... + 455015152.

It is an arithmetic number, because the mean of its divisors is an integer number (2730090852).

Almost surely, 2^10010333113 is an apocalyptic number.

It is an amenable number.

10010333113 is a deficient number, since it is larger than the sum of its proper divisors (910030295).

10010333113 is an equidigital number, since it uses as much as digits as its factorization.

10010333113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 910030294.

The product of its (nonzero) digits is 81, while the sum is 16.

Adding to 10010333113 its reverse (31133301001), we get a palindrome (41143634114).

The spelling of 10010333113 in words is "ten billion, ten million, three hundred thirty-three thousand, one hundred thirteen".