10011001133121 has 4 divisors (see below), whose sum is σ = 13348001510832. Its totient is φ = 6674000755412.

The previous prime is 10011001133087. The next prime is 10011001133167. The reversal of 10011001133121 is 12133110011001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10011001133121 - 2¹¹ = 10011001131073 is a prime.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 10011001133121.

It is not an unprimeable number, because it can be changed into a prime (10011001133171) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1668500188851 + ... + 1668500188856.

It is an arithmetic number, because the mean of its divisors is an integer number (3337000377708).

Almost surely, 2^{10011001133121} is an apocalyptic number.

It is an amenable number.

10011001133121 is a deficient number, since it is larger than the sum of its proper divisors (3337000377711).

10011001133121 is an equidigital number, since it uses as much as digits as its factorization.

10011001133121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3337000377710.

The product of its (nonzero) digits is 18, while the sum is 15.

Adding to 10011001133121 its reverse (12133110011001), we get a palindrome (22144111144122).

The spelling of 10011001133121 in words is "ten trillion, eleven billion, one million, one hundred thirty-three thousand, one hundred twenty-one".