Base | Representation |
---|---|
bin | 101110100111100000… |
… | …1011101010111110011 |
3 | 100120101211200110110212 |
4 | 1131033001131113303 |
5 | 3120011131432243 |
6 | 113553453214335 |
7 | 10142551134422 |
oct | 1351701352763 |
9 | 316354613425 |
10 | 100110030323 |
11 | 39502558556 |
12 | 1749a7913ab |
13 | 9595555844 |
14 | 4bb99032b9 |
15 | 290dc21318 |
hex | 174f05d5f3 |
100110030323 has 4 divisors (see below), whose sum is σ = 100110862368. Its totient is φ = 100109198280.
The previous prime is 100110030313. The next prime is 100110030329. The reversal of 100110030323 is 323030011001.
It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.
It is a cyclic number.
It is not a de Polignac number, because 100110030323 - 236 = 31390553587 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 100110030298 and 100110030307.
It is not an unprimeable number, because it can be changed into a prime (100110030329) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 197168 + ... + 488973.
It is an arithmetic number, because the mean of its divisors is an integer number (25027715592).
Almost surely, 2100110030323 is an apocalyptic number.
100110030323 is a deficient number, since it is larger than the sum of its proper divisors (832045).
100110030323 is an equidigital number, since it uses as much as digits as its factorization.
100110030323 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 832044.
The product of its (nonzero) digits is 54, while the sum is 14.
Adding to 100110030323 its reverse (323030011001), we get a palindrome (423140041324).
The spelling of 100110030323 in words is "one hundred billion, one hundred ten million, thirty thousand, three hundred twenty-three".
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