Base | Representation |
---|---|
bin | 101110100111100010… |
… | …1100010110010111001 |
3 | 100120101220200212022202 |
4 | 1131033011202302321 |
5 | 3120011420213423 |
6 | 113553532155545 |
7 | 10142563214312 |
oct | 1351705426271 |
9 | 316356625282 |
10 | 100111101113 |
11 | 3950311a001 |
12 | 1749b008bb5 |
13 | 959583c04a |
14 | 4bb9b01609 |
15 | 290dd83728 |
hex | 174f162cb9 |
100111101113 has 4 divisors (see below), whose sum is σ = 101605296720. Its totient is φ = 98616905508.
The previous prime is 100111101107. The next prime is 100111101127. The reversal of 100111101113 is 311101111001.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 100111101113 - 218 = 100110838969 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 100111101094 and 100111101103.
It is not an unprimeable number, because it can be changed into a prime (100111101143) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 747097703 + ... + 747097836.
It is an arithmetic number, because the mean of its divisors is an integer number (25401324180).
Almost surely, 2100111101113 is an apocalyptic number.
It is an amenable number.
100111101113 is a deficient number, since it is larger than the sum of its proper divisors (1494195607).
100111101113 is an equidigital number, since it uses as much as digits as its factorization.
100111101113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1494195606.
The product of its (nonzero) digits is 3, while the sum is 11.
Adding to 100111101113 its reverse (311101111001), we get a palindrome (411212212114).
The spelling of 100111101113 in words is "one hundred billion, one hundred eleven million, one hundred one thousand, one hundred thirteen".
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