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10011201193 = 71430171599
BaseRepresentation
bin10010101001011011…
…01100111010101001
3221211200211201021101
421110231230322221
5131000331414233
64333222441401
7503041543330
oct112455547251
927750751241
1010011201193
1142780756a4
121b34893261
13c3710c9b6
146ad83ad17
153d8d71c7d
hex254b6cea9

10011201193 has 4 divisors (see below), whose sum is σ = 11441372800. Its totient is φ = 8581029588.

The previous prime is 10011201119. The next prime is 10011201197. The reversal of 10011201193 is 39110211001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-10011201193 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 10011201193.

It is not an unprimeable number, because it can be changed into a prime (10011201197) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 715085793 + ... + 715085806.

It is an arithmetic number, because the mean of its divisors is an integer number (2860343200).

Almost surely, 210011201193 is an apocalyptic number.

It is an amenable number.

10011201193 is a deficient number, since it is larger than the sum of its proper divisors (1430171607).

10011201193 is an equidigital number, since it uses as much as digits as its factorization.

10011201193 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1430171606.

The product of its (nonzero) digits is 54, while the sum is 19.

Adding to 10011201193 its reverse (39110211001), we get a palindrome (49121412194).

The spelling of 10011201193 in words is "ten billion, eleven million, two hundred one thousand, one hundred ninety-three".

Divisors: 1 7 1430171599 10011201193