100113000033 has 4 divisors (see below), whose sum is σ = 133484000048. Its totient is φ = 66742000020.

The previous prime is 100113000023. The next prime is 100113000047. The reversal of 100113000033 is 330000311001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 100113000033 - 2⁶ = 100112999969 is a prime.

It is a super-2 number, since 2×100113000033² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 100112999982 and 100113000018.

It is not an unprimeable number, because it can be changed into a prime (100113000023) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16685500003 + ... + 16685500008.

It is an arithmetic number, because the mean of its divisors is an integer number (33371000012).

Almost surely, 2^100113000033 is an apocalyptic number.

It is an amenable number.

100113000033 is a deficient number, since it is larger than the sum of its proper divisors (33371000015).

100113000033 is an equidigital number, since it uses as much as digits as its factorization.

100113000033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 33371000014.

The product of its (nonzero) digits is 27, while the sum is 12.

Adding to 100113000033 its reverse (330000311001), we get a palindrome (430113311034).

The spelling of 100113000033 in words is "one hundred billion, one hundred thirteen million, thirty-three", and thus it is an aban number.