10012002121313 has 4 divisors (see below), whose sum is σ = 10012008664368. Its totient is φ = 10011995578260.

The previous prime is 10012002121309. The next prime is 10012002121327. The reversal of 10012002121313 is 31312120021001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 10012002121313 - 2² = 10012002121309 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10012002121291 and 10012002121300.

It is not an unprimeable number, because it can be changed into a prime (10012002421313) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 388970 + ... + 4491692.

It is an arithmetic number, because the mean of its divisors is an integer number (2503002166092).

Almost surely, 2^{10012002121313} is an apocalyptic number.

It is an amenable number.

10012002121313 is a deficient number, since it is larger than the sum of its proper divisors (6543055).

10012002121313 is an equidigital number, since it uses as much as digits as its factorization.

10012002121313 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6543054.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 10012002121313 its reverse (31312120021001), we get a palindrome (41324122142314).

The spelling of 10012002121313 in words is "ten trillion, twelve billion, two million, one hundred twenty-one thousand, three hundred thirteen".