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100121301331 = 591696971209
BaseRepresentation
bin101110100111110110…
…0011101000101010011
3100120102121220002101121
41131033230131011103
53120022023120311
6113554534543111
710143046006462
oct1351754350523
9316377802347
10100121301331
1139508956637
12174a2507a97
1395979a0a8c
144bbb1d89d9
15290ebeab71
hex174fb1d153

100121301331 has 4 divisors (see below), whose sum is σ = 101818272600. Its totient is φ = 98424330064.

The previous prime is 100121301289. The next prime is 100121301353. The reversal of 100121301331 is 133103121001.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 100121301331 - 29 = 100121300819 is a prime.

It is a super-2 number, since 2×1001213013312 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (100121302331) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 848485546 + ... + 848485663.

It is an arithmetic number, because the mean of its divisors is an integer number (25454568150).

Almost surely, 2100121301331 is an apocalyptic number.

100121301331 is a deficient number, since it is larger than the sum of its proper divisors (1696971269).

100121301331 is an equidigital number, since it uses as much as digits as its factorization.

100121301331 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1696971268.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 100121301331 its reverse (133103121001), we get a palindrome (233224422332).

The spelling of 100121301331 in words is "one hundred billion, one hundred twenty-one million, three hundred one thousand, three hundred thirty-one".

Divisors: 1 59 1696971209 100121301331