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10012131305563 = 23793414207943
BaseRepresentation
bin1001000110110010000110…
…0001111010100001011011
31022110011001122102102112211
42101230201201322201123
52303014321103234223
633143302025015551
72052231642630142
oct221544141724133
938404048372484
1010012131305563
113210137119492
1211585026245b7
135781a8574b3a
1426883836a759
15125689e9dd0d
hex91b2187a85b

10012131305563 has 4 divisors (see below), whose sum is σ = 10012137892848. Its totient is φ = 10012124718280.

The previous prime is 10012131305543. The next prime is 10012131305611. The reversal of 10012131305563 is 36550313121001.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-10012131305563 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (10012131305513) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 275370 + ... + 4483312.

It is an arithmetic number, because the mean of its divisors is an integer number (2503034473212).

Almost surely, 210012131305563 is an apocalyptic number.

10012131305563 is a deficient number, since it is larger than the sum of its proper divisors (6587285).

10012131305563 is an equidigital number, since it uses as much as digits as its factorization.

10012131305563 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6587284.

The product of its (nonzero) digits is 8100, while the sum is 31.

Adding to 10012131305563 its reverse (36550313121001), we get a palindrome (46562444426564).

The spelling of 10012131305563 in words is "ten trillion, twelve billion, one hundred thirty-one million, three hundred five thousand, five hundred sixty-three".

Divisors: 1 2379341 4207943 10012131305563