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10012200000113 = 109158439157037
BaseRepresentation
bin1001000110110010010110…
…0111111101101001110001
31022110011020102200110202102
42101230211213331221301
52303014441200000423
633143312521230145
72052233435545613
oct221544547755161
938404212613672
1010012200000113
113210171978743
121158521632355
135781b98773bc
1426884352cdb3
1512569101cc28
hex91b259fda71

10012200000113 has 8 divisors (see below), whose sum is σ = 10021612386240. Its totient is φ = 10002788047120.

The previous prime is 10012200000013. The next prime is 10012200000119. The reversal of 10012200000113 is 31100000221001.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 10012200000113 - 222 = 10012195805809 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10012200000094 and 10012200000103.

It is not an unprimeable number, because it can be changed into a prime (10012200000119) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 63678431 + ... + 63835467.

It is an arithmetic number, because the mean of its divisors is an integer number (1252701548280).

Almost surely, 210012200000113 is an apocalyptic number.

It is an amenable number.

10012200000113 is a deficient number, since it is larger than the sum of its proper divisors (9412386127).

10012200000113 is a wasteful number, since it uses less digits than its factorization.

10012200000113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 216567.

The product of its (nonzero) digits is 12, while the sum is 11.

Adding to 10012200000113 its reverse (31100000221001), we get a palindrome (41112200221114).

The spelling of 10012200000113 in words is "ten trillion, twelve billion, two hundred million, one hundred thirteen", and thus it is an aban number.

Divisors: 1 1091 58439 157037 63756949 171327367 9177085243 10012200000113