Base | Representation |
---|---|
bin | 1001000110110010010110… |
… | …0111111101101001110001 |
3 | 1022110011020102200110202102 |
4 | 2101230211213331221301 |
5 | 2303014441200000423 |
6 | 33143312521230145 |
7 | 2052233435545613 |
oct | 221544547755161 |
9 | 38404212613672 |
10 | 10012200000113 |
11 | 3210171978743 |
12 | 1158521632355 |
13 | 5781b98773bc |
14 | 26884352cdb3 |
15 | 12569101cc28 |
hex | 91b259fda71 |
10012200000113 has 8 divisors (see below), whose sum is σ = 10021612386240. Its totient is φ = 10002788047120.
The previous prime is 10012200000013. The next prime is 10012200000119. The reversal of 10012200000113 is 31100000221001.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 10012200000113 - 222 = 10012195805809 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 10012200000094 and 10012200000103.
It is not an unprimeable number, because it can be changed into a prime (10012200000119) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 63678431 + ... + 63835467.
It is an arithmetic number, because the mean of its divisors is an integer number (1252701548280).
Almost surely, 210012200000113 is an apocalyptic number.
It is an amenable number.
10012200000113 is a deficient number, since it is larger than the sum of its proper divisors (9412386127).
10012200000113 is a wasteful number, since it uses less digits than its factorization.
10012200000113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 216567.
The product of its (nonzero) digits is 12, while the sum is 11.
Adding to 10012200000113 its reverse (31100000221001), we get a palindrome (41112200221114).
The spelling of 10012200000113 in words is "ten trillion, twelve billion, two hundred million, one hundred thirteen", and thus it is an aban number.
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