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100122032433 = 3291150827959
BaseRepresentation
bin101110100111110111…
…1001111100100110001
3100120102200021020021110
41131033233033210301
53120022220014213
6113555002343533
710143055143123
oct1351757174461
9316380236243
10100122032433
1139509305955
12174a27baba9
139597b98797
144bbb349213
15290ece25c3
hex174fbcf931

100122032433 has 8 divisors (see below), whose sum is σ = 138099355200. Its totient is φ = 64446365648.

The previous prime is 100122032393. The next prime is 100122032453. The reversal of 100122032433 is 334230221001.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 100122032433 - 210 = 100122031409 is a prime.

It is not an unprimeable number, because it can be changed into a prime (100122032453) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 575413893 + ... + 575414066.

It is an arithmetic number, because the mean of its divisors is an integer number (17262419400).

Almost surely, 2100122032433 is an apocalyptic number.

It is an amenable number.

100122032433 is a deficient number, since it is larger than the sum of its proper divisors (37977322767).

100122032433 is a wasteful number, since it uses less digits than its factorization.

100122032433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1150827991.

The product of its (nonzero) digits is 864, while the sum is 21.

Adding to 100122032433 its reverse (334230221001), we get a palindrome (434352253434).

The spelling of 100122032433 in words is "one hundred billion, one hundred twenty-two million, thirty-two thousand, four hundred thirty-three".

Divisors: 1 3 29 87 1150827959 3452483877 33374010811 100122032433