1001222031113 has 4 divisors (see below), whose sum is σ = 1001854516608. Its totient is φ = 1000589545620.

The previous prime is 1001222031091. The next prime is 1001222031137. The reversal of 1001222031113 is 3111302221001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1001222031113 - 2⁸ = 1001222030857 is a prime.

It is a super-2 number, since 2×1001222031113² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1001222031091 and 1001222031100.

It is not an unprimeable number, because it can be changed into a prime (1001222031193) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 316240373 + ... + 316243538.

It is an arithmetic number, because the mean of its divisors is an integer number (250463629152).

Almost surely, 2^{1001222031113} is an apocalyptic number.

It is an amenable number.

1001222031113 is a deficient number, since it is larger than the sum of its proper divisors (632485495).

1001222031113 is an equidigital number, since it uses as much as digits as its factorization.

1001222031113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 632485494.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 1001222031113 its reverse (3111302221001), we get a palindrome (4112524252114).

The spelling of 1001222031113 in words is "one trillion, one billion, two hundred twenty-two million, thirty-one thousand, one hundred thirteen".