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10012233300403 = 14967196196647
BaseRepresentation
bin1001000110110010011110…
…0110111111100110110011
31022110011022202100022011111
42101230213212333212303
52303020023211103103
633143320111054151
72052234321601165
oct221544746774663
938404282308144
1010012233300403
113210189752744
121158530811357
135781c3736609
14268847b1a935
15125693de986d
hex91b279bf9b3

10012233300403 has 4 divisors (see below), whose sum is σ = 10079429497200. Its totient is φ = 9945037103608.

The previous prime is 10012233300373. The next prime is 10012233300457. The reversal of 10012233300403 is 30400333221001.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 10012233300403 - 213 = 10012233292211 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (10012233300473) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33598098175 + ... + 33598098472.

It is an arithmetic number, because the mean of its divisors is an integer number (2519857374300).

Almost surely, 210012233300403 is an apocalyptic number.

10012233300403 is a deficient number, since it is larger than the sum of its proper divisors (67196196797).

10012233300403 is an equidigital number, since it uses as much as digits as its factorization.

10012233300403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 67196196796.

The product of its (nonzero) digits is 1296, while the sum is 22.

Adding to 10012233300403 its reverse (30400333221001), we get a palindrome (40412566521404).

The spelling of 10012233300403 in words is "ten trillion, twelve billion, two hundred thirty-three million, three hundred thousand, four hundred three".

Divisors: 1 149 67196196647 10012233300403