10013001440411 has 4 divisors (see below), whose sum is σ = 10017546608952. Its totient is φ = 10008456271872.

The previous prime is 10013001440383. The next prime is 10013001440437. The reversal of 10013001440411 is 11404410031001.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 10013001440411 - 2³⁴ = 9995821571227 is a prime.

It is a super-3 number, since 3×10013001440411³ (a number of 40 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (10013001440471) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2272580966 + ... + 2272585371.

It is an arithmetic number, because the mean of its divisors is an integer number (2504386652238).

Almost surely, 2^{10013001440411} is an apocalyptic number.

10013001440411 is a deficient number, since it is larger than the sum of its proper divisors (4545168541).

10013001440411 is an equidigital number, since it uses as much as digits as its factorization.

10013001440411 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4545168540.

The product of its (nonzero) digits is 192, while the sum is 20.

Adding to 10013001440411 its reverse (11404410031001), we get a palindrome (21417411471412).

The spelling of 10013001440411 in words is "ten trillion, thirteen billion, one million, four hundred forty thousand, four hundred eleven".