Base | Representation |
---|---|
bin | 10110110001000111010010… |
… | …111110111111110000111001 |
3 | 111010112112111001220210022002 |
4 | 112301013102332333300321 |
5 | 101111031031222113423 |
6 | 552544020215510345 |
7 | 30043210042156004 |
oct | 2661072276776071 |
9 | 433475431823262 |
10 | 100132112301113 |
11 | 299a5876a56402 |
12 | b2923359883b5 |
13 | 43b4557824699 |
14 | 1aa25c4a4a53b |
15 | b899eccca228 |
hex | 5b11d2fbfc39 |
100132112301113 has 8 divisors (see below), whose sum is σ = 100502040174720. Its totient is φ = 99762187638960.
The previous prime is 100132112301047. The next prime is 100132112301163. The reversal of 100132112301113 is 311103211231001.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-100132112301113 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (100132112301163) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 74792918 + ... + 76119936.
It is an arithmetic number, because the mean of its divisors is an integer number (12562755021840).
Almost surely, 2100132112301113 is an apocalyptic number.
It is an amenable number.
100132112301113 is a deficient number, since it is larger than the sum of its proper divisors (369927873607).
100132112301113 is a wasteful number, since it uses less digits than its factorization.
100132112301113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1605727.
The product of its (nonzero) digits is 108, while the sum is 20.
Adding to 100132112301113 its reverse (311103211231001), we get a palindrome (411235323532114).
The spelling of 100132112301113 in words is "one hundred trillion, one hundred thirty-two billion, one hundred twelve million, three hundred one thousand, one hundred thirteen".
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