100133000123113 has 4 divisors (see below), whose sum is σ = 100214342935168. Its totient is φ = 100051657311060.

The previous prime is 100133000123111. The next prime is 100133000123243. The reversal of 100133000123113 is 311321000331001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 100133000123113 - 2¹ = 100133000123111 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (100133000123111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 40671404181 + ... + 40671406642.

It is an arithmetic number, because the mean of its divisors is an integer number (25053585733792).

Almost surely, 2^{100133000123113} is an apocalyptic number.

It is an amenable number.

100133000123113 is a deficient number, since it is larger than the sum of its proper divisors (81342812055).

100133000123113 is an equidigital number, since it uses as much as digits as its factorization.

100133000123113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 81342812054.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 100133000123113 its reverse (311321000331001), we get a palindrome (411454000454114).

The spelling of 100133000123113 in words is "one hundred trillion, one hundred thirty-three billion, one hundred twenty-three thousand, one hundred thirteen".