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100133102003 = 119103009273
BaseRepresentation
bin101110101000001100…
…1011110000110110011
3100120110110002121212112
41131100121132012303
53120033033231003
6114000035515535
710143251215664
oct1352031360663
9316413077775
10100133102003
1139514586660
12174a6458bab
13959a27311c
144bbc9cb36b
152910c7c3d8
hex175065e1b3

100133102003 has 4 divisors (see below), whose sum is σ = 109236111288. Its totient is φ = 91030092720.

The previous prime is 100133101987. The next prime is 100133102033. The reversal of 100133102003 is 300201331001.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 100133102003 - 24 = 100133101987 is a prime.

It is a super-2 number, since 2×1001331020032 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (100133102033) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4551504626 + ... + 4551504647.

It is an arithmetic number, because the mean of its divisors is an integer number (27309027822).

Almost surely, 2100133102003 is an apocalyptic number.

100133102003 is a deficient number, since it is larger than the sum of its proper divisors (9103009285).

100133102003 is an equidigital number, since it uses as much as digits as its factorization.

100133102003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9103009284.

The product of its (nonzero) digits is 54, while the sum is 14.

Adding to 100133102003 its reverse (300201331001), we get a palindrome (400334433004).

The spelling of 100133102003 in words is "one hundred billion, one hundred thirty-three million, one hundred two thousand, three".

Divisors: 1 11 9103009273 100133102003