Base | Representation |
---|---|
bin | 10110110001001000001111… |
… | …001000001011101100011011 |
3 | 111010112122002101121101111111 |
4 | 112301020033020023230123 |
5 | 101111040113030422420 |
6 | 552544304303041151 |
7 | 30043244043653602 |
oct | 2661101710135433 |
9 | 433478071541444 |
10 | 100133121342235 |
11 | 299a6244594993 |
12 | b2925778a01b7 |
13 | 43b46888a8b37 |
14 | 1aa267ca6ca39 |
15 | b89a5b69545a |
hex | 5b120f20bb1b |
100133121342235 has 8 divisors (see below), whose sum is σ = 120282734097216. Its totient is φ = 80024504749440.
The previous prime is 100133121342203. The next prime is 100133121342251. The reversal of 100133121342235 is 532243121331001.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 100133121342235 - 25 = 100133121342203 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 100133121342197 and 100133121342206.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 10249035171 + ... + 10249044940.
It is an arithmetic number, because the mean of its divisors is an integer number (15035341762152).
Almost surely, 2100133121342235 is an apocalyptic number.
100133121342235 is a deficient number, since it is larger than the sum of its proper divisors (20149612754981).
100133121342235 is an equidigital number, since it uses as much as digits as its factorization.
100133121342235 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 20498081093.
The product of its (nonzero) digits is 12960, while the sum is 31.
Adding to 100133121342235 its reverse (532243121331001), we get a palindrome (632376242673236).
The spelling of 100133121342235 in words is "one hundred trillion, one hundred thirty-three billion, one hundred twenty-one million, three hundred forty-two thousand, two hundred thirty-five".
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