1001350113 has 4 divisors (see below), whose sum is σ = 1335133488. Its totient is φ = 667566740.

The previous prime is 1001350067. The next prime is 1001350121. The reversal of 1001350113 is 3110531001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1001350113 - 2¹⁶ = 1001284577 is a prime.

It is a super-2 number, since 2×1001350113² = 2005404097610225538, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1001350092 and 1001350101.

It is not an unprimeable number, because it can be changed into a prime (1001350153) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 166891683 + ... + 166891688.

It is an arithmetic number, because the mean of its divisors is an integer number (333783372).

Almost surely, 2^1001350113 is an apocalyptic number.

It is an amenable number.

1001350113 is a deficient number, since it is larger than the sum of its proper divisors (333783375).

1001350113 is an equidigital number, since it uses as much as digits as its factorization.

1001350113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 333783374.

The product of its (nonzero) digits is 45, while the sum is 15.

The square root of 1001350113 is about 31644.1165621668. The cubic root of 1001350113 is about 1000.4498352845.

Adding to 1001350113 its reverse (3110531001), we get a palindrome (4111881114).

The spelling of 1001350113 in words is "one billion, one million, three hundred fifty thousand, one hundred thirteen".