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100140011331 = 3295232200831
BaseRepresentation
bin101110101000011001…
…1110100111101000011
3100120110221002122200120
41131100303310331003
53120041320330311
6114000443551323
710143364023543
oct1352063647503
9316427078616
10100140011331
1139518475748
12174a882b543
13959b821c99
144bbd8a9323
152911694706
hex1750cf4f43

100140011331 has 16 divisors (see below), whose sum is σ = 138388316160. Its totient is φ = 64334662560.

The previous prime is 100140011329. The next prime is 100140011369. The reversal of 100140011331 is 133110041001.

It is not a de Polignac number, because 100140011331 - 21 = 100140011329 is a prime.

It is a super-3 number, since 3×1001400113313 (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a self number, because there is not a number n which added to its sum of digits gives 100140011331.

It is not an unprimeable number, because it can be changed into a prime (100140011831) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1054915 + ... + 1145916.

It is an arithmetic number, because the mean of its divisors is an integer number (8649269760).

Almost surely, 2100140011331 is an apocalyptic number.

100140011331 is a deficient number, since it is larger than the sum of its proper divisors (38248304829).

100140011331 is a wasteful number, since it uses less digits than its factorization.

100140011331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2201386.

The product of its (nonzero) digits is 36, while the sum is 15.

Adding to 100140011331 its reverse (133110041001), we get a palindrome (233250052332).

The spelling of 100140011331 in words is "one hundred billion, one hundred forty million, eleven thousand, three hundred thirty-one".

Divisors: 1 3 29 87 523 1569 15167 45501 2200831 6602493 63824099 191472297 1151034613 3453103839 33380003777 100140011331