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1001411433 = 321110115267
BaseRepresentation
bin111011101100000…
…101001101101001
32120210022222020100
4323230011031221
54022330131213
6243211420013
733546566601
oct7354051551
92523288210
101001411433
114742a8260
1223b454609
1312c612759
1496dd7c01
155cdae773
hex3bb05369

1001411433 has 12 divisors (see below), whose sum is σ = 1577981808. Its totient is φ = 606915960.

The previous prime is 1001411431. The next prime is 1001411443. The reversal of 1001411433 is 3341141001.

It is not a de Polignac number, because 1001411433 - 21 = 1001411431 is a prime.

It is a super-2 number, since 2×10014114332 = 2005649716286226978, which contains 22 as substring.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (1001411431) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 5057535 + ... + 5057732.

It is an arithmetic number, because the mean of its divisors is an integer number (131498484).

Almost surely, 21001411433 is an apocalyptic number.

It is an amenable number.

1001411433 is a deficient number, since it is larger than the sum of its proper divisors (576570375).

1001411433 is a wasteful number, since it uses less digits than its factorization.

1001411433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10115284 (or 10115281 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 18.

The square root of 1001411433 is about 31645.0854478227. The cubic root of 1001411433 is about 1000.4702564908.

Adding to 1001411433 its reverse (3341141001), we get a palindrome (4342552434).

The spelling of 1001411433 in words is "one billion, one million, four hundred eleven thousand, four hundred thirty-three".

Divisors: 1 3 9 11 33 99 10115267 30345801 91037403 111267937 333803811 1001411433