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100145055545 = 520029011109
BaseRepresentation
bin101110101000100011…
…1000100011100111001
3100120111021120221001022
41131101013010130321
53120044113234140
6114001144032225
710143454632653
oct1352107043471
9316437527038
10100145055545
1139520300517
12174aa462675
13959c899c22
144bc041d6d3
152911d3e0b5
hex17511c4739

100145055545 has 4 divisors (see below), whose sum is σ = 120174066660. Its totient is φ = 80116044432.

The previous prime is 100145055511. The next prime is 100145055587. The reversal of 100145055545 is 545550541001.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 545550541001 = 599246619339.

It can be written as a sum of positive squares in 2 ways, for example, as 52398872464 + 47746183081 = 228908^2 + 218509^2 .

It is a cyclic number.

It is not a de Polignac number, because 100145055545 - 224 = 100128278329 is a prime.

It is a super-2 number, since 2×1001450555452 (a number of 23 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10014505550 + ... + 10014505559.

It is an arithmetic number, because the mean of its divisors is an integer number (30043516665).

Almost surely, 2100145055545 is an apocalyptic number.

It is an amenable number.

100145055545 is a deficient number, since it is larger than the sum of its proper divisors (20029011115).

100145055545 is an equidigital number, since it uses as much as digits as its factorization.

100145055545 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 20029011114.

The product of its (nonzero) digits is 50000, while the sum is 35.

Adding to 100145055545 its reverse (545550541001), we get a palindrome (645695596546).

The spelling of 100145055545 in words is "one hundred billion, one hundred forty-five million, fifty-five thousand, five hundred forty-five".

Divisors: 1 5 20029011109 100145055545