10016565131 has 4 divisors (see below), whose sum is σ = 10043858592. Its totient is φ = 9989271672.

The previous prime is 10016565107. The next prime is 10016565161. The reversal of 10016565131 is 13156561001.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 10016565131 - 2¹⁸ = 10016302987 is a prime.

It is a super-3 number, since 3×10016565131³ (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10016565094 and 10016565103.

It is not an unprimeable number, because it can be changed into a prime (10016565161) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13646180 + ... + 13646913.

It is an arithmetic number, because the mean of its divisors is an integer number (2510964648).

Almost surely, 2^10016565131 is an apocalyptic number.

10016565131 is a deficient number, since it is larger than the sum of its proper divisors (27293461).

10016565131 is an equidigital number, since it uses as much as digits as its factorization.

10016565131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 27293460.

The product of its (nonzero) digits is 2700, while the sum is 29.

The spelling of 10016565131 in words is "ten billion, sixteen million, five hundred sixty-five thousand, one hundred thirty-one".