100201102012121 has 4 divisors (see below), whose sum is σ = 109310293104144. Its totient is φ = 91091910920100.

The previous prime is 100201102012001. The next prime is 100201102012183. The reversal of 100201102012121 is 121210201102001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-100201102012121 is a prime.

It is a super-2 number, since 2×100201102012121² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 100201102012096 and 100201102012105.

It is not an unprimeable number, because it can be changed into a prime (100201102012421) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4554595545995 + ... + 4554595546016.

It is an arithmetic number, because the mean of its divisors is an integer number (27327573276036).

Almost surely, 2^{100201102012121} is an apocalyptic number.

100201102012121 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

100201102012121 is a deficient number, since it is larger than the sum of its proper divisors (9109191092023).

100201102012121 is an equidigital number, since it uses as much as digits as its factorization.

100201102012121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9109191092022.

The product of its (nonzero) digits is 16, while the sum is 14.

Adding to 100201102012121 its reverse (121210201102001), we get a palindrome (221411303114122).

The spelling of 100201102012121 in words is "one hundred trillion, two hundred one billion, one hundred two million, twelve thousand, one hundred twenty-one".