Base | Representation |
---|---|
bin | 10110110010000111101000… |
… | …111111011110011000011011 |
3 | 111010210010210222111102211002 |
4 | 112302013220333132120123 |
5 | 101113144024424031021 |
6 | 553035443554255215 |
7 | 30051204112346654 |
oct | 2662075077363033 |
9 | 433703728442732 |
10 | 100201201002011 |
11 | 29a220aa7a8a1a |
12 | b2a37b758750b |
13 | 43bac1821a6a5 |
14 | 1aa5a9a60452b |
15 | b8b6e33cb50b |
hex | 5b21e8fde61b |
100201201002011 has 4 divisors (see below), whose sum is σ = 100213825578552. Its totient is φ = 100188576425472.
The previous prime is 100201201001999. The next prime is 100201201002047. The reversal of 100201201002011 is 110200102102001.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 100201201002011 - 218 = 100201200739867 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 100201201001983 and 100201201002001.
It is not an unprimeable number, because it can be changed into a prime (100201201002311) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6312276365 + ... + 6312292238.
It is an arithmetic number, because the mean of its divisors is an integer number (25053456394638).
Almost surely, 2100201201002011 is an apocalyptic number.
100201201002011 is a deficient number, since it is larger than the sum of its proper divisors (12624576541).
100201201002011 is an equidigital number, since it uses as much as digits as its factorization.
100201201002011 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 12624576540.
The product of its (nonzero) digits is 8, while the sum is 11.
Adding to 100201201002011 its reverse (110200102102001), we get a palindrome (210401303104012).
The spelling of 100201201002011 in words is "one hundred trillion, two hundred one billion, two hundred one million, two thousand, eleven".
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