10020210112121 has 4 divisors (see below), whose sum is σ = 10931138304144. Its totient is φ = 9109281920100.

The previous prime is 10020210112111. The next prime is 10020210112139. The reversal of 10020210112121 is 12121101202001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10020210112121 - 2¹⁰ = 10020210111097 is a prime.

It is a super-2 number, since 2×10020210112121² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10020210112096 and 10020210112105.

It is not an unprimeable number, because it can be changed into a prime (10020210112111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 455464095995 + ... + 455464096016.

It is an arithmetic number, because the mean of its divisors is an integer number (2732784576036).

Almost surely, 2^{10020210112121} is an apocalyptic number.

10020210112121 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

10020210112121 is a deficient number, since it is larger than the sum of its proper divisors (910928192023).

10020210112121 is an equidigital number, since it uses as much as digits as its factorization.

10020210112121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 910928192022.

The product of its (nonzero) digits is 16, while the sum is 14.

Adding to 10020210112121 its reverse (12121101202001), we get a palindrome (22141311314122).

The spelling of 10020210112121 in words is "ten trillion, twenty billion, two hundred ten million, one hundred twelve thousand, one hundred twenty-one".