10021143121 has 4 divisors (see below), whose sum is σ = 10932156144. Its totient is φ = 9110130100.

The previous prime is 10021143113. The next prime is 10021143133. The reversal of 10021143121 is 12134112001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10021143121 - 2³ = 10021143113 is a prime.

It is a super-3 number, since 3×10021143121³ (a number of 31 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10021143095 and 10021143104.

It is not an unprimeable number, because it can be changed into a prime (10021143161) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 455506495 + ... + 455506516.

It is an arithmetic number, because the mean of its divisors is an integer number (2733039036).

Almost surely, 2^10021143121 is an apocalyptic number.

10021143121 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

10021143121 is a deficient number, since it is larger than the sum of its proper divisors (911013023).

10021143121 is an equidigital number, since it uses as much as digits as its factorization.

10021143121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 911013022.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 10021143121 its reverse (12134112001), we get a palindrome (22155255122).

The spelling of 10021143121 in words is "ten billion, twenty-one million, one hundred forty-three thousand, one hundred twenty-one".