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100214413435 = 520042882687
BaseRepresentation
bin101110101010100111…
…1101001100001111011
3100120200010002200012001
41131111033221201323
53120214342212220
6114012102401431
710145256313363
oct1352517514173
9316603080161
10100214413435
1139556473094
1217509730277
1395b10723b6
144bc97159a3
152917e8e80a
hex17553e987b

100214413435 has 4 divisors (see below), whose sum is σ = 120257296128. Its totient is φ = 80171530744.

The previous prime is 100214413433. The next prime is 100214413469. The reversal of 100214413435 is 534314412001.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 100214413435 - 21 = 100214413433 is a prime.

It is a super-2 number, since 2×1002144134352 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (100214413433) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10021441339 + ... + 10021441348.

It is an arithmetic number, because the mean of its divisors is an integer number (30064324032).

Almost surely, 2100214413435 is an apocalyptic number.

100214413435 is a deficient number, since it is larger than the sum of its proper divisors (20042882693).

100214413435 is an equidigital number, since it uses as much as digits as its factorization.

100214413435 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 20042882692.

The product of its (nonzero) digits is 5760, while the sum is 28.

Adding to 100214413435 its reverse (534314412001), we get a palindrome (634528825436).

The spelling of 100214413435 in words is "one hundred billion, two hundred fourteen million, four hundred thirteen thousand, four hundred thirty-five".

Divisors: 1 5 20042882687 100214413435