100216113 has 4 divisors (see below), whose sum is σ = 133621488. Its totient is φ = 66810740.

The previous prime is 100216097. The next prime is 100216147. The reversal of 100216113 is 311612001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 311612001 = 3 ⋅103870667.

It is a cyclic number.

It is not a de Polignac number, because 100216113 - 2⁴ = 100216097 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 100216092 and 100216101.

It is not an unprimeable number, because it can be changed into a prime (100216213) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16702683 + ... + 16702688.

It is an arithmetic number, because the mean of its divisors is an integer number (33405372).

Almost surely, 2^100216113 is an apocalyptic number.

It is an amenable number.

100216113 is a deficient number, since it is larger than the sum of its proper divisors (33405375).

100216113 is an equidigital number, since it uses as much as digits as its factorization.

100216113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 33405374.

The product of its (nonzero) digits is 36, while the sum is 15.

The square root of 100216113 is about 10010.7998181963. The cubic root of 100216113 is about 464.4930120075.

Adding to 100216113 its reverse (311612001), we get a palindrome (411828114).

The spelling of 100216113 in words is "one hundred million, two hundred sixteen thousand, one hundred thirteen".